Exercise 1.1 (Revised) - Chapter 1 - Integers - Ncert Solutions class 7 - Maths
Updated On 26-08-2025 By Lithanya
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Chapter 1 - Integers | NCERT Solutions for Class 7 Maths
Ex 1.1 Question 1.
Write down a pair of integers whose:
(a) sum is -7
(b) difference is -10
(c) sum is 0
Answer:
(a) One such pair whose sum is $-7:(-5,-2)(-10,3)$
(b) One such pair whose difference is -10: $(-2,8),(-11,-1)$
(c) One such pair whose sum is 0 : $(5,5),(6,6)$
Ex 1.1 Question 2.
(a) Write a pair of negative integers whose difference gives 8.
(b) Write a negative integer and a positive integer whose is -5 .
(c) Write a negative integer and a positive integer whose difference is -3 .
Answer:
(a) $(-2,-10)(-5,-13)$
(b) $(-7,2),(-9,4)$
(c) $(-1,2),(-2,1)$
Ex 1.1 Question 3.
In a quiz, team A scored -40,10, 0 and team B scores 0, 10, -40 in three successive rounds. Which team scored more? Can we say that we can add integers in any order?
Answer:
Team A scored $-40,10,0$
Total score of Team $A=-40+10+0=-30$
Team B scored $0,10,-40$
Total score of Team B $=0+10+(-40)=0+10-40=-30$
Thus, scores of both teams are same.
Yes, we can add integers in any order due to commutative property.
Ex 1.1 Question 4.
Fill in the blanks to make the following statements true:
(i) $(-5)+(-8)=(-8)+(\ldots \ldots$.
(ii) $-53+\ldots \ldots . .=-53$
(iii) $17+\ldots . . .=0$
(iv) $[13+(-12)]+(\ldots \ldots)=13+[(-12)+(-7)]$
(v) $(-4)+[15+(-3)]=[-4+15]+\ldots \ldots$.
Answer:
(i) $(-5)+(-8)=(-8)+(-5)$ [Commutative property]
(ii) $-53+\underline{0}=-53$ [Zero additive property]
(iii) $17+(-17)=0$ (Additive identity]
(iv) $[13+(12)]+(-7)=13+[(-12)+(-7)]$ [Associative property]
$(-4)+[15+(-3)]=[-4+15]+\underline{(-3)}$ [Associative property]
