Exercise 2.3 (Revised) - Chapter 2 - Fractions & Decimals - Ncert Solutions class 7 - Maths

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Chapter 2: Fractions & Decimals - NCERT Solutions for Class 7 Maths

Ex 2.3 Question 1.

Find:
(i) $12 \div \frac{3}{4}$
(ii) $14 \div \frac{5}{6}$
(iii) $8 \div \frac{7}{3}$
(iv) $4 \div \frac{8}{3}$
(v) $3 \div 2 \frac{1}{3}$
(vi) $5 \div 3 \frac{4}{7}$

Answer:

(i) $12 \div \frac{3}{4}=12 \times \frac{4}{3}=16$
(ii) $14 \div \frac{5}{6}=14 \times \frac{6}{5}=\frac{84}{5}=16 \frac{4}{5}$
(iii) $8 \div \frac{7}{3}=8 \times \frac{3}{7}=\frac{24}{7}=3 \frac{3}{7}$
(iv) $4 \div \frac{8}{3}=4 \times \frac{3}{8}=\frac{3}{2}=1 \frac{1}{2}$
(v) $3 \div 2 \frac{1}{3}=3 \div \frac{7}{3}=3 \times \frac{3}{7}=\frac{9}{7}=1 \frac{2}{7}$
(vi) $5 \div 3 \frac{4}{7}=5 \div \frac{25}{7}=5 \times \frac{7}{25}=\frac{7}{5}=1 \frac{2}{5}$

Ex 2.3 Question 2.

Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fraction, improper fractions and whole numbers.
(i) $\frac{3}{7}$
(ii) $\frac{5}{8}$
(iii) $\frac{9}{7}$
(iv) $\frac{6}{5}$

(v) $\frac{12}{7}$
(vi) $\frac{1}{8}$
(vii) $\frac{1}{11}$

Answer:

(i) Reciprocal of $\frac{3}{7}=\frac{7}{3} \rightarrow$ Improper fraction
(ii) Reciprocal of $\frac{5}{8}=\frac{8}{5} \rightarrow$ Improper fraction
(iii) Reciprocal of $\frac{9}{7}=\frac{7}{9} \rightarrow$ Proper fraction
(iv) Reciprocal of $\frac{6}{5}=\frac{5}{6} \rightarrow$ Proper fraction
(v)Reciprocal of $\frac{12}{7}=\frac{7}{12} \rightarrow$ Proper fraction
(vi) Reciprocal of $\frac{1}{8}=8 \rightarrow$ Whole number
(vi) Reciprocal of $\frac{1}{11}=11 \rightarrow$ Whole number

Ex 2.3 Question 3.

Find:
(i) $\frac{7}{3} \div 2$
(ii) $\frac{4}{9} \div 5$
(iii) $\frac{6}{13} \div 7$
(iv) $4 \frac{1}{3} \div 3$

(v) $3 \frac{1}{2} \div 4$
(vi) $4 \frac{3}{7} \div 7$

Answer:

(i) $\frac{7}{3} \div 2=\frac{7}{3} \times \frac{1}{2}=\frac{7 \times 1}{3 \times 2}=\frac{7}{6}=1 \frac{1}{6}$
(ii) $\frac{4}{9} \div 5=\frac{4}{9} \times \frac{1}{5}=\frac{4 \times 1}{9 \times 5}=\frac{4}{45}$
(iii) $\frac{6}{13} \div 7=\frac{6}{13} \times \frac{1}{7}=\frac{6 \times 1}{13 \times 7}=\frac{6}{91}$
(iv) $4 \frac{1}{3} \div 3=\frac{13}{3} \div 3=\frac{13}{3} \times \frac{1}{3}=\frac{13}{9}=1 \frac{4}{9}$

(v) $3 \frac{1}{2} \div 4=\frac{7}{2} \div 4=\frac{7}{2} \times \frac{1}{4}=\frac{7}{8}$
(vi) $4 \frac{3}{7} \div 7=\frac{31}{7} \div 7=\frac{31}{7} \times \frac{1}{7}=\frac{31}{49}$

(v) $3 \frac{1}{2} \div 4=\frac{7}{2} \div 4=\frac{7}{2} \times \frac{1}{4}=\frac{7}{8}$
(vi) $4 \frac{3}{7} \div 7=\frac{31}{7} \div 7=\frac{31}{7} \times \frac{1}{7}=\frac{31}{49}$

Ex 2.3 Question 4.

Find:
(i) $\frac{2}{5} \div \frac{1}{2}$
(ii) $\frac{4}{9} \div \frac{2}{3}$
(iii) $\frac{3}{7} \div \frac{8}{7}$
(iv) $2 \frac{1}{3} \div \frac{3}{5}$
(v) $3 \frac{1}{2} \div \frac{8}{3}$
(vi) $\frac{2}{5} \div 1 \frac{1}{2}$
(vii) $3 \frac{1}{5} \div 1 \frac{2}{3}$
(viii) $2 \frac{1}{5} \div 1 \frac{1}{5}$

Answer:

(i) $\frac{2}{5} \div \frac{1}{2}=\frac{2}{5} \times \frac{2}{1}=\frac{2 \times 2}{5 \times 1}=\frac{4}{5}$
(ii) $\frac{4}{9} \div \frac{2}{3}=\frac{4}{9} \times \frac{3}{2}=\frac{2}{3}$
(iii) $\frac{3}{7} \div \frac{8}{7}=\frac{3}{7} \times \frac{7}{8}=\frac{3}{8}$
(iv) $2 \frac{1}{3} \div \frac{3}{5}=\frac{7}{3} \div \frac{3}{5}=\frac{7}{3} \times \frac{5}{3}=\frac{35}{9}=3 \frac{8}{9}$

(v) $3 \frac{1}{2} \div \frac{8}{3}=\frac{7}{2} \div \frac{8}{3}=\frac{7}{2} \times \frac{3}{8}=\frac{7 \times 3}{2 \times 8}=\frac{21}{16}=1 \frac{5}{16}$
(vi) $\frac{2}{5} \div 1 \frac{1}{2}=\frac{2}{5} \div \frac{3}{2}=\frac{2}{5} \times \frac{2}{3}=\frac{2 \times 2}{5 \times 3}=\frac{4}{15}$
(vii) $3 \frac{1}{5} \div 1 \frac{2}{3}=\frac{16}{5} \div \frac{5}{3}=\frac{16}{5} \times \frac{3}{5}=\frac{16 \times 3}{5 \times 5}=\frac{48}{25}=1 \frac{23}{25}$
(viii) $2 \frac{1}{5} \div 1 \frac{1}{5}=\frac{11}{5} \div \frac{6}{5}=\frac{11}{5} \times \frac{5}{6}=\frac{11}{6}=1 \frac{5}{6}$