Exercise 2.4 (Revised) - Chapter 2 - Fractions & Decimals - Ncert Solutions class 7 - Maths

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Chapter 2: Fractions & Decimals - NCERT Solutions for Class 7 Maths

Ex 2.4 Question 1.

Find:
(i) $0.2 \times 6$
(ii) $8 \times 4.6$
(iii) $2.71 \times 5$
(iv) $20.1 \times 4$
(v) $0.05 \times 7$
(vi) $211.02 \times 4$
(vii) $2 \times 0.86$

Answer:

(i) $0.2 \times 6=1.2$
(ii) $8 \times 4.6=36.8$
(iii) $2.71 \times 5=13.55$
(iv) $20.1 \times 4=80.4$
(v) $0.05 \times 7=0.35$
(vi) $211.02 \times 4=844.08$
(vii) $2 \times 0.86=1.72$

Ex 2.4 Question 2.

Find the area of rectangle whose length is $5.7 \mathrm{~cm}$ and breadth is $3 \mathrm{~cm}$ ?
Answer:

Given: Length of rectangle $=5.7 \mathrm{~cm}$ and Breadth of rectangle $=3 \mathrm{~cm}$
Area of rectangle $=$ Length $\mathrm{x}$ Breadth

$
=5.7 \times 3=17.1 \mathrm{~cm}^2
$

Thus, the area of rectangle is $17.1 \mathrm{~cm}^2$.
Ex 2.4 Question 3.

Find:
(i) $1.3 \times 10$
(ii) $36.8 \times 10$
(iii) $153.7 \times 10$
(iv) $168.07 \times 10$
(v) $31.1 \times 100$
(vi) $156.1 \times 100$
(vii) $3.62 \times 100$
(viii) $3.07 \times 100$
(ix) $0.5 \times 10$
(x) $0.08 \times 10$
(xi) $0.9 \times 100$
(xii) $0.03 \times 1000$

Answer:

(i) $1.3 \times 10=13.0$
(ii) $36.8 \times 10=368.0$
(iii) $153.7 \times 10=1537.0$
(iv) $168.07 \times 10=1680.7$
(v) $31.1 \times 100=3110.0$
(vi) $156.1 \times 100=15610.0$

(vii) $3.62 \times 100=362.0$
(viii) $43.07 \times 100=4307.0$
(ix) $0.5 \times 10=5.0$
(x) $0.08 \times 10=0.80$
(xi) $0.9 \times 100=90.0$
(xii) $0.03 \times 1000=30.0$

Ex 2.4 Question 4.

A two-wheeler covers a distance of $55.3 \mathrm{~km}$ in one litre of petrol. How much distance will it cover in 10 litres of petrol?

Answer:

$\because$ In one litre, a two-wheeler covers a distance $=55.3 \mathrm{~km}$
$\therefore$ In 10 litrs, a two- wheeler covers a distance $=55.3 \times 10=553.0 \mathrm{~km}$
Thus, $553 \mathrm{~km}$ distance will be covered by it in 10 litres of petrol.
Ex 2.4 Question 5.

Find:

(i) $2.5 \times 0.3$
(ii) $0.1 \times 51.7$
(iii) $0.2 \times 316.8$
(iv) $1.3 \times 3.1$
(v) $0.5 \times 0.05$
(vi) $11.2 \times 0.15$
(vii) $1.07 \times 0.02$
(viii) $10.05 \times 1.05$
(ix) $101.01 \times 0.01$
(x) $100.01 \times 1.1$

Answer:

(i) $2.5 \times 0.3=0.75$
(ii) $0.1 \times 51.7=5.17$
(iii) $0.2 \times 316.8=63.36$
(iv) $1.3 \times 3.1=4.03$
(v) $0.5 \times 0.05=0.025$
(vi) $11.2 \times 0.15=1.680$
(vii) $1.07 \times 0.02=0.0214$
(viii) $10.05 \times 1.05=10.5525$
(ix) $101.01 \times 0.01=1.0101$
(x) $100.01 \times 1.1=110.11$