Exercise 6.2 (Revised) - Chapter 6 - Triangles & Its Properties - Ncert Solutions class 7 - Maths

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Chapter 6 - Triangles & Its Properties | NCERT Solutions Class 7 Maths

Ex 6.2 Question 1

$\text {.Find the value of the unknown exterior angle } x \text { in the following diagrams: }$

Answer:

Since, Exterior angle = Sum of opposite interior angles, therefore
1. $x=50^{\circ}+70^{\circ}=120^{\circ}$
2. $x=65^{\circ}+45^{\circ}=110^{\circ}$
3. $x=30^{\circ}+40^{\circ}=70^{\circ}$
4. $x=60^{\circ}+60^{\circ}=120^{\circ}$
5. $x=50^{\circ}+50^{\circ}=100^{\circ}$
6. $x=60^{\circ}+30^{\circ}=90^{\circ}$

Ex 6.2 Question 2.

Find the value of the unknown interior angle $x$ in the following figures:

Answer:

Since, Exterior angle = Sum of opposite interior angles, therefore
1. $x+50^{\circ}=115^{\circ} \Rightarrow x=115^{\circ}-50^{\circ}=65^{\circ}$
2. $70^{\circ}+x=100^{\circ} \Rightarrow x=100^{\circ}-70^{\circ}=30^{\circ}$
3. $x+90^{\circ}=125^{\circ} \Rightarrow x=125^{\circ}-90^{\circ}=35^{\circ}$
4. $60^{\circ}+x=120^{\circ} \Rightarrow x=120^{\circ}-60^{\circ}=60^{\circ}$
5. $30^{\circ}+x=80^{\circ} \Rightarrow x=80^{\circ}-30^{\circ}=50^{\circ}$
6. $x+35^{\circ}=75^{\circ} \Rightarrow x=75^{\circ}-35^{\circ}=40^{\circ}$