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Page No 87: - Chapter 3 - Electrochemistry - Intext Solutions - Ncert Solutions class 12 - Chemistry

Updated On 26-08-2025 By Lithanya


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Question 3.10:

If a current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons would flow through the wire?

Answer:

= 0.5 A

t = 2 hours = 2 × 60 × 60 s = 7200 s

Thus, Q = It

= 0.5 A × 7200 s

= 3600 C

We know that https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/262/6255/NCERT(INTEXT)_17-11-08_Utpal_12_Chemistry_3_15_html_1bc29ed2.gif  number of electrons.

Then,

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/262/6255/NCERT(INTEXT)_17-11-08_Utpal_12_Chemistry_3_15_html_202941eb.gif

Hence, https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/262/6255/NCERT(INTEXT)_17-11-08_Utpal_12_Chemistry_3_15_html_3c6201b9.gif number of electrons will flow through the wire.

Question 3.11:

Suggest a list of metals that are extracted electrolytically.

Answer:

Metals that are on the top of the reactivity series such as sodium, potassium, calcium, lithium, magnesium, aluminium are extracted electrolytically.

Question 3.12:

What is the quantity of electricity in coulombs needed to reduce 1 mol of

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/262/6257/NCERT(INTEXT)_17-11-08_Utpal_12_Chemistry_3_15_html_m1d462c49.gif ? Consider the reaction:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/262/6257/NCERT(INTEXT)_17-11-08_Utpal_12_Chemistry_3_15_html_m5ee57577.gif

Answer:

The given reaction is as follows:

https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/262/6257/NCERT(INTEXT)_17-11-08_Utpal_12_Chemistry_3_15_html_5c5cd94a.gif

Therefore, to reduce 1 mole of https://img-nm.mnimgs.com/img/study_content/curr/1/12/17/262/6257/NCERT(INTEXT)_17-11-08_Utpal_12_Chemistry_3_15_html_m1d462c49.gif , the required quantity of electricity will be:

=6 F

= 6 × 96487 C

= 578922 C