Page No 220: - Chapter 8 - D & F - Block Elements - Intext Solutions - Ncert Solutions class 12 - Chemistry

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Question 8.6:

Why is the highest oxidation state of a metal exhibited in its oxide or fluoride only?

Answer:

Both oxide and fluoride ions are highly electronegative and have a very small size. Due to these properties, they are able to oxidize the metal to its highest oxidation state.

Question 8.7:

Which is a stronger reducing agent Cr²⁺ or Fe²⁺ and why?

Answer:

The following reactions are involved when Cr²⁺ and Fe²⁺ act as reducing agents.

Cr²⁺   Cr³⁺ Fe²⁺   Fe³⁺

The  value is −0.41 V and   is +0.77 V. This means that Cr²⁺ can be easily oxidized to Cr³⁺, but Fe²⁺ does not get oxidized to Fe³⁺ easily. Therefore, Cr²⁺ is a better reducing agent that Fe³⁺.